The function is continuous and .
Mean value theorem for integrals:
\If is continuous on
, then there exist a number
in
such that
.
Since the function is continuous on , so by the mean value theorem, there exist a number
in
.
such that
\.
We have, .
Substitue in
.
.
From the above expression it is observed that there exist a number in
such that .
Therefore, the function value takes on the value on
.
The function value takes on the value atleast once on
.