\"\"

\

The equation is \"\".

\

Consider \"\".

\

Consider the interval \"\".

\

Find \"\":

\

\"\"

\

\"\".

\

Find \"\":

\

\"\"

\

\"\".

\

Here \"\" and \"\".

\

Hence by intermediate value theorem, thre exist a number \"\" in \"\", such that \"\".

\

\"\" has a solution on \"\".

\

\"\"

\

(b)

\

Consider \"\".

\

Differentiate on each side with respect to \"\".

\

\"\"

\

\"\"

\

Newtons approximation formula : \"\".

\

\"\".

\

Consider \"\".

\

Substitutte \"\" in \"\".

\

\"\"

\

Substitutte \"\" in \"\".

\

\"\".

\

Substitutte \"\" in above expression.

\

\"\"

\

Similarly,

\

\"\"

\

Root of the equation is \"\".

\

\"\"

\

(a)

\

\"\" has a solution on \"\".

\

(b)

\

Root of the equation is \"\".