(a).

The size of poulation growth after years is .

Observe the table :

Consider initial year is and population is  .

The time between every two consecutive years is years.

Then consider year  , hence .

The population growth equation is .

Substitute , and in the equation .

The population growth equation is .

The population growth equation is .

Find the population for the year .

For the year , then .

Substitute in the equation .

million.

The population for the year is million.

Find the population for the year .

For the year , then .

Substitute in the equation  

million.

The population for the year is million.

According to the table, the population for the year is million.

Hence the equation is not appropiate as the difference is to high.

(b).

Observe  the table.

Consider initial year was  and  the population is .

The time between every two consecutive years is years.

Then consider year  , hence .

The population growth equation is .

Substitute ,   and in the equation .

The population growth equation is .

Observe the table year was .

Substitute in the equation  

million.

According to the table, the population for the year is million.

Hence the prediction is appropiate as the difference is low.

(c).

Observe  the table ,consider initial year was  and  .

The time between every two years is years.

Then consider year  ,hence .

The population growth equation is .

Substitute and   and in the equation

The population growth equation is .

Observe the table year was .

Substitute in the equation   .

million

According to the table, the population for the year is million.

Hence the prediction is appropiate as the difference is low.

(a). million and million.

(b). million.

(c). million.