\
(a)
\The definite integral is .
Determine by left end points:
Observe the graph of .
Number of subintervals are .
Width of the interval is :.
Left end points are and
.
Riemann sum is .
.
Substitute corresponding function values in above expression from the graph.
\Area under the graph of the function using left endpoints is .
.
Determine using right endpoints.
Number of subintervals are .
Width of the interval is :.
Right end points are and
.
Riemann sum is .
.
Substitute corresponding function values in above expression observe from the graph.
\Area under the graph of the function using right endpoints is .
.
Determine by Mid points:
Number of subintervals are .
Width of the interval is :.
, where
.
Mid points are and
.
Riemann sum is .
.
Substitute corresponding function values in above expression from the given graph.
\Area under the graph of the function using mid points is .
.
\
(b)
\Consder the graph is approximately equal to sum of the area of the right angle triangle and rectangle.
\Area of the triangle is .
From the graph, and
.
Therefore, area of the graph is
\
Area of the rectangle is .
.
Total area under the graph is
Actual area of the graph is 8 units.
\Now compare and
values with actual area value.
Therefore, is an underestimate and
are over estimates.
\
(c)
\Find :
Trapezoidal rule:
\Where, .
\
Substitute corresponding values in the above expression.
\\
(d)
\For any value of , the values of
and
.
Observe the results in step 1, 2, and 3.
\.
\
(a)
\,
and
(b)
\ is an underestimate and
are over estimates.
\
(c)
(d)
\.