\"\"

\

The equation is \"\".

\

Where \"\" is the objects distance above the surface at time \"\".

\

\"\" is the radius of earth, \"\" is the mass of the object  and \"\" is acceleration.

\

From newtons second law: \"\".

\

Therefore, \"\".

\

(a) Show that \"\".

\

The velocity of the object is \"\".

\

\"\".

\

Using chain rule : \"\".

\

\"\"

\

Since \"\".

\

\"\"

\

Multiply each side by \"\".

\

\"\"

\

Susbtitute \"\" .

\

\"\"

\

\"\"

\

\"\"

\

Integrate both sides.

\

\"\"

\

The initial velocity is \"\" and maximum height is \"\".

\

Rewrite the above integral .

\

\"\" \ \

\

\"\"

\

\"\"

\

\"\"

\

\"\"

\

\"\"

\

\"\".

\

Therefore, the initial velocity is \"\".

\

\"\"

\

(b)

\

The initial velocity is \"\".

\

Find the escape velocity \"\".

\

Substitute \"\".

\

\"\"

\

\"\"

\

\"\"

\

\"\"

\

Therefore, the escape velocity \"\".

\

\"\"

\

(c)

\

The escape velocity \"\".

\

Substitute \"\" and \"\".

\

Since \"\".

\

\"\"

\

\"\"

\

Hence, \"\".

\

\"\".

\

Therefore, the escape velocity is \"\" and \"\".

\

\"\"

\

(a) The initial velocity is \"\".

\

(b) The escape velocity \"\".

\

(c) The escape velocity is \"\" and \"\".