The equation is .
(a) Find that the function is increasing when the condition is .
Consider
.
Consider .
.
If , then
and
.
Hence, .
The value of when
.
Therefore, the function is increasing when .
Show that the function is decreasing when the condition is .
If , then
and
.
Hence the product is .
Therefore, the function is decreasing when .
(b)
\The function is .
Substitute in
.
Graph the differential equation . \ \
Graph :
\Observe the graph:
\When, the vaue of
.
the value of
.
the value of
.
Find the equilibrium solutions of the funtion.
\The equilibrium solutions occur when .
Substitute and equate the function to zero.
.
Equilibrium occurs when .
(c)
\The function is \ \
Apply integral on each side.
\.
At the initial condiition and
.
Substitute in
.
.
Therefore , the solution is .
(d)
\If ,show that atleast one value of
, the value of
.
The function is .
Equate the function .
When , the value of
has atleast a single value for
.
(a) The function is increasing when and the function is decreasing when
.
(b)
\
When the vaue of
.
the value of
.
the value of
.
The Equilibrium conditions are .
(c) The solution is .
(d) The value of have atleast a single value for
.