The differential equation is .
The solution of the differential equation with is
,
where is the carrying capacity and
is called as learning curve.
Jim processed units during first hour and
units during second hour.
Therefore two points are and
.
The solution passes through :
The solution passes through :
Equate the equations and
.
.
Therefore, Jim can process a maximum of units per hour.
Mark processed units during first hour and
units during second hour.
Therefore, two points are and
.
The solution passes through :
The solution passes through :
Equate the equations and
.
Therefore, Mark can process a maximum of units per hour.
Jim can process a maximum of units per hour.
Mark can process a maximum of units per hour.