\"\"

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The curves are \"\" and \"\".

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Find area of the triangle. \ \

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Area is enclosed by the \"\"-axis is \"\".

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Area of the region enclosed by \"\"-axis then equate \"\" is equal to zero to find intersection of curve with \"\"-axis.

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\"\"

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The curve is \"\".

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Differentiate on each side with respect to \"\".

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\"\"

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\"\"

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\"\"

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\"\".

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Substitute \"\" and \"\" and integral limit.

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\"\"

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Consider \"\" and \"\".

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\"\" and \"\".

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Integration by parts: \"\".

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\"\"

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\"\"

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Area is enclosed by the \"\"-axis is \"\" sq-units.

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\"\"

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Area is enclosed by the \"\"-axis is \"\" sq-units.