\"\"

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The power series is \"\".

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Radius of the convergence of the series is \"\".

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Find the radius of the convergence of \"\".

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Differentiation and integration of power series.

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Theorem 2:

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If the power series \"\" has radius of convergence \"\" then the function \"\" is differentiable on the interval \"\"  and

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(i) \"\", (ii) \"\" then the radii of the power series in (i) and (ii) are both \"\".

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Here \"\" is the derivative of the sum \"\".

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Therefore by theorem 2, radius of the convergence of \"\" is also \"\".\"\"

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Radius of the convergence of \"\" is \"\".