\"\"

\

Vector equation of the plane \"\" with the point \"\" and normal vector \"\" is  \"\".

\

\"\"

\

The plane that passes through the point \"\" and contains the line of itersection of the planes \"\" and \"\".

\

Here \"\" and \"\".

\

The resulting vector is \"\".

\

\"\"

\

\"\"

\

\"\"

\

The vector is \"\".

\

Find the second point line of intersecition substitute \"\" in \"\" and \"\".

\

\"\" and \"\".

\

Add the above two equations.

\

\"\"

\

\"\".

\

Substitute \"\" in \"\".

\

\"\".

\

The another vector is \"\".

\

\"\"

\

Since \"\" and \"\" lie in the same plane, the cross product is orthogonal to the that plane and it can be represented as perpendicular vector \"\".

\

\"\"

\

Hence the vector \"\".

\

\"\"

\

Vector equation of the plane \"\" with the point \"\" and normal vector \"\" is

\

\

\"\".

\

Here \"\" and \"\".

\

Substitute above values in vector equation formula.

\

\"\"

\

\"\"

\

\"\".

\

\"\"

\

The equation of the plane is \"\".