Vector equation of the plane with the point
and normal vector
is
.
The plane that passes through the point and contains the line of itersection of the planes
and
.
Here and
.
The resulting vector is .
The vector is .
Find the second point line of intersecition substitute in
and
.
and
.
Add the above two equations.
\.
Substitute in
.
.
The another vector is .
Since and
lie in the same plane, the cross product is orthogonal to the that plane and it can be represented as perpendicular vector
.
Hence the vector .
Vector equation of the plane with the point
and normal vector
is
\
.
Here and
.
Substitute above values in vector equation formula.
\.
The equation of the plane is .