The equation is and points are
and
.
The equation is .
Apply derivative on each side with respect to .
.
.
Consider the point .
The derivative of the equation at the point
is the slope of the line.
.
The line equation is .
Substitute and
in the line equation.
The tangent line equation is .
Normal line is perpendicular to tangent line then,
\slope of tangent line slope of normal line is equal to
.
Let slope of the normal as .
Therefore, .
.
point slope form of line equation is .
Substitute and
in the above equation.
The normal line equation is .
The equation is .
Apply derivative on each side with respect to .
.
.
Consider the point .
The derivative of the equation at the point
is the slope of the line.
.
The line equation is .
Substitute and
in the line equation.
The tangent line is .
Normal line is perpendicular to tangent line then,
\slope of tangent line slope of normal line is equal to
.
Let slope of the normal as .
Therefore,
.
point slope form of line equation is .
Substitute and
in the above equation.
The normal line equation is .
Graph:
\Graph the conic equation .
Graph the tangent line equations and
.
Graph the normal line equations and
.
A the point :
The tangent line equation is .
The normal line equation is .
As the point :
The tangent line is .
The normal line equation is .
Graph:
\Graph of the conic equation , the tangent line equations
and
and the normal line equations
and
is
.