\"\"

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The function is \"\".

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Use the mean value theorem to show that the function has atleast one real root.

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Mean value Theorem :

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If \"\" is continuous on \"\" and differentiable on open interval \"\", then there exists a number \"\" in \"\".

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The function \"\" is continuous and differentiable, since it is a polynomial function.

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\"\"

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\"\"

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So the function have atleast one real root on open interval \"\".

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\"\"

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Use the Rolles theorem to show that the function has only one real root.

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Rolle\"\"s Theorem :

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Let \"\" be a function that satisfies the following three hypotheses.

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1. \"\" is continuous on \"\".

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2. \"\" is differentiable on \"\".

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3. \"\".

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Then there is a number \"\" in \"\" such that \"\".

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The function \"\" is continuous and differentiable, since it is a polynomial function.

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Suppose \"\", \"\" are distinct real numbers such that \"\".

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\"\"

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Apply derivative with respect to \"\".

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\"\"

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From the Rolles theorem number \"\" in \"\" such that \"\".

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\"\"

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Therefore the function does not have the real roots while equting \"\".

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From Rolles theorem, above four root are imaginary.

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But according to Mean value theorem the remaining one root is real.

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It is clear that the functon have only real root.

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\"\"

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The function \"\" has exactly one real solution.