The function is .
Use the mean value theorem to show that the function has atleast one real root.
\Mean value Theorem :
\If is continuous on
and differentiable on open interval
, then there exists a number
in
.
The function is continuous and differentiable.
So the function have atleast one real root on open interval .
Use the Rolles theorem to show that the function has only one real root.
\Rolles Theorem :
Let be a function that satisfies the following three hypotheses.
1. is continuous on
.
2. is differentiable on
.
3. .
Then there is a number in
such that
.
The function is continuous and differentiable.
Suppose ,
are distinct real numbers such that
.
Apply derivative with respect to .
From the Rolles theorem number in
such that
.
Range of the sine function is to
.
Therefore the function does not have roots while equting .
But according to Mean value theorem the remaining one root is real.
\It is clear that the functon have only real root.
\The function has exactly one real solution.