\

\

\

The function is

\"\"

.

\

\

Apply derivative on each side with respect to

\"\"

.

\

\"\"

\

\

The sign changes of

\"\"

:

\

\

\"\"

on

\"\"

.

\

\

\"\"

on

\"\"

.

\

\

\"\"

on

\"\"

.

\

\

\

\

\

$\"\"$

\

$\"\"$ on $\"\"$ .

\

So $\"\"$ on $\"\"$ .

\

Therefore $\"\"$ .

\

\

\

\

\

\

\"\"

.