\"\"

\

(a)

\

Motion of particle is \"\".

\

Find the velocity of particle by applying derivative.

\

\"\"

\

Therefore the velocity of particle is \"\".

\

Equate it to zero.

\

\"\"

\

So the critical numbers are \"\" and \"\".

\

\"\"

\

(b)

\

Consider the test intervals to find the interval of increasing and decreasing.

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
Test intervalTest valueSign of \"\"Conclusion
\"\"\"\" \

\"\"

\
Increasing
\"\"\"\" \

\"\"

\
Decreasing
\"\"\"\" \

\"\"

\
Increasing
\

 The sign of the velocity function is positive on the intervals \"\" and \"\".

\

(c)

\

The sign of the velocity function is negative on the intervals \"\".

\

\"\"

\

(d)

\

At \"\" and \"\", the velocity function changes its sign.

\

\"\"

\

(a) The velocity of particle is \"\".

\

(b) The sign of the velocity function is positive on the intervals \"\" and \"\".

\

(c) The sign of the velocity function is negative on the intervals \"\".

\

(d) Velocity function changes its direction at \"\" and \"\".