The function is in the interval
.
The domain of the is
,
,
and
.
Find the inflection points.
\Differentiate with respect to
.
Differentiate with respect to
.
Find the inflection points by equating to zero.
is never euqals to zero.
Therefore the function does not have any inflection points.
\Consider the test intervals ,
,
and
.
\
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Up | \
![]() | \
![]() | \
![]() | \
Down | \
![]() | \
![]() | \
\
| \
Up | \
![]() | \
![]() | \
\
| \
Down | \
Concavity test :
\(a) If for all
in
, then the graph of
is concave upward on
.
(b) If for all
in
, then the graph of
is concave downward on
.
Thus, the graph is concave up in the intervals and
.
The graph is concave down in the intervals and
.
Function does not have any inflection points.
\The function is concave up in the intervals
and
.
The graph is concave down in the intervals and
.