The function is in the interval
.
Find the inflection points.
\Differentiate with respect to
.
Differentiate with respect to
.
Find the inflection points by equating to zero.
Therefore the function have inflection points at and
.
Consider the test intervals ,
and
.
\
Interval \ | Test Value | Sign of ![]() | Concavity |
![]() | ![]() | \
| Down |
![]() | ![]() | \
| Up |
![]() | ![]() | \
| Down |
Concavity test :
\(a) If for all
in
, then the graph of
is concave upward on
.
(b) If for all
in
, then the graph of
is concave downward on
.
Thus, the graph is concave up in the interval .
The graph is concave down in the intervals and
.
The function have inflection points at and
.
The function is concave up in the interval
.
The graph is concave down in the intervals and
.