The function is ,
.
Apply first derivative with respect to .
Find the relative extrema, by equating .
The general solution of sine function is
.
Where
Then,
Substitute in
.
Substitute in
.
Substitute in
.
Substitute in
.
Therefore and
are the solution in the given interval.
So the critical values of are
and
.
Now, substitute in
.
Now, substitute in
.
The relative extrema points are and
.
Using the second derivative test.
\Apply second derivative with respect to .
Point | \![]() | \
![]() | \
Sign of ![]() | \
\
| \
\
| \
Conclusion | \Neither | \Neither | \
Therefore does not have any relative extrema.