The function is .
The domain of a function is all possible values of .
The domain of the function is .
Intercept :
\To find the -intercept, substitute
in the function.
Apply zero product property.
\ and
and
and
.
The -intercepts are
and
.
To find the -intercept, substitute
in the function.
The -intercept is
.
Find the extrema.
\The function is .
Apply derivative on each side with respect to .
Apply product rule of derivatives: .
In this case and
.
.
To find the critical numbers by equating .
.
The critical numbers are .
.
The domain of is
.
Relative extrema points exist at critical numbers.
\The test intervals are ,
and
.
Perform first derivative test to identify the nature of the extrema.
\Test itervals | \Test value | \Sign of ![]() | \
Conclusion | \
![]() | \
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\
| \
Decreasing | \
![]() | \
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\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
The function has relative maximum at .
Substitute in
.
The relative minimum at .
Substitute in
.
The relative maximum at .
Inflection points:
\.
Again apply derivative on each side with respect to .
Apply quotient rule of derivatives: .
Find inflection points by equating .
and
and
and
and
.
is not in the domain.
Therefore, there is inflection point is at .
Substitute in
.
The inflection point is .
Consider the test intervals as .
\
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
\
Up \ | \
![]() | \
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\
| \
Down | \
Asymptotes :
\Vertical asymptote:
\Vertical asymptote exist when denominator is zero.
\Equate denominator to zero.
\The function is .
There is no vertical asymptote.
\Horizontal asymptote:
\The line is called a horizontal asymptote of the curve
if either \ \
or
.
.
There is no horizontal asymptote.
\Graph:
\Graph the function .
Graph:
\Graph the function .
.