The function is ,
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The function appears to be continuous on the interval .
To find the function is one-to-one function, differentiate .
Since the derivative of the function is a positive value, the function is one to one function and is strictly monotonic.
\To find the inverse of the function, let us assume and solve the x in terms of y.
Now interchange x and y, substitute .
,
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The function is is one to one function and is strictly monotonic.
The inverse of is
,
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