Statement : If , where
is odd then
exists.
The statement is true.
\Because, if is odd then only the fuction has an inverse function since if
is even then the function is not an one to one.
Verify by the followin description.
\Consider .
.
Therefore, the function is not an one to one.
If is odd then every element is mapped with different element and therefore the function is an one to one.
And it is strictly monotonic.
\From the theorem 5.7 :
\If the function is strictly monotonic and it is one to one therefore the function has an inverse function.
Therefore, if , where
is odd then
exists.
The statement is true.
\True.