The parametric equation of path of projectile motion is and
.
Here is the initial velocity.
is the angle made with respect to ground.
is the height above the ground.
(a)
\Eliminate parameter from the parametric equations.
Consider .
.
Substitute in
.
The rectangular equation is
(b)
\The rectangular equation is .
Compare the equation with
Here .
Find .
Initial velocity is .
The parametric equation of path of projectile motion is and
.
Substitute ,
and
.
and
and
.
The parametric equations are and
.
(c)
\The parametric equations are and
.
The rectangular equation is .
Graph:
\Graph the parametric equations and
.
Graph the rectangular equation .
Observe the graph:
\The graphs obtained parametric equations is equal to the rectangular equations.
\(d)
\The rectangular equation is .
Find the maximum height.
\Maximum height of a object in a projectile motion occurs when vertical component of velocitu is zero.
\In simple, this is a point where we draw the line of symmetry.
\Find the range.
\Range is the horizontal distance travelled during projectile motion.
\Graph:
\Graph the rectangular equation .
Observe the graph:
\Maximum height is .
Range is .
(a) The rectangular equation is
(b) ,
and
.
The parametric equations is and
.
(c) The graphs obtained parametric equations is equal to the rectangular equations.
\(d)
\Maximum height is .Range is
.