The function is .
All possible values of is the domain of the function.
Since it is a rational function, the denominator of the function should not be the zero.
\ and
and
Therefore, the domain of the function is all real numbers of except
and
.
Domain in set-builder notation is .
The domain in interval notation is .
Ana thinks the domain is .
Mason thinks the domain is .
So Ana is wrong.
\Mason answer is correct.
\ \Mason answer is correct.