\"\"

\

The function is \"\" and the value of \"\".

\

Setup the synthetic division using a zero place for the missing terms \"\" in the dividend.

\

Perform synthetic substitution method to evaluate \"\" for \"\".\"\"

\

Since the remainder is \"\", \"\".

\

\"\"

\

Check the function at \"\" at \"\" using direct substitution method.\"\"

\

The result is verified.

\

\"\"

\

The remainder of \"\"  at \"\" is \"\".

\

Since the remainder is non zero, \"\" is not a solution of the given equation.