Dividend is .
Divisor is .
Since the remainder is ,
is a solution of
.
Write the terms of the dividend so that the degrees of the terms are in descending order.
\Then write just the coefficients as shown below.
\Write the constant of the divisor
to the left.
In this case, , so bring the first coefficient,
, down.
Multiply the sum, by
:
.
Write the product under the next coefficient, and add :
.
Multiply the sum, by
:
.
Write the product under the next coefficient, and add :
.
Multiply the sum, by
:
.
Write the product under the next coefficient, and add :
.
The remainder is last entry in the last row.
\Therefore, the remainder .
The remainder is .
Therefore, when ,
will have the remainder
.
The value of is
.