(a).
\Identify Possible Rational Zeros:
\Usually it is not practical to test all possible zeros of a polynomial function using only synthetic substitution. The Rational Zero Theorem can be used for finding the some possible zeros to test.
\\
The function is .
Because the leading coefficient is , the possible rational zeros are the intezer factors of the constant term
.
Therefore the possible rational zeros of are
.
Examine the variations in sign for and
:
Consider .
The original polynomial equation has variations in sign.
.
.
There are no sign changes.so ,there are no negative roots.
\Therefore by Descartes rule of signs
has either
or
positive real zeros and no negative real zeros.
Synthetic Division:
\Consider .
Setup the synthetic division using a zero place for the missing term term in the dividend.
.
Perform the synthetic division method by testing and
.
Since , conclude that
is a zero of
.
Therefore, is a rational zero.
The depressed polynomial is .
Consider .
Perform the synthetic substitution division on the depressed polynomial by testing and
.
Since , conclude that
is a zero of
.
Therefore, is a rational zero.
Therefore, and
are the factors of
.
The remaining quadratic factor is does not have rational zeros.
To find the rational zeros use the quadratic formula .
Consider .
Where
Substiute the values in the quadratic formula .
.
The rational zeros are and
.
So is written as a product of linear and irreducable quadratic factors is
.
(b).
\ written as a product of linear factors is
.
(c).
\Because the function has degree , by the corollary of the fundemental therom of algebra
has excatly
zeros,including any that may be repeated.
The linear factorization yeilds zeros:
.
(a).
\The function is written as a product of linear and irreducable quadratic factors is
.
(b).
\ written as a product of linear factors is
.
(c).
\The zeros are .