The inequality is .
The inequality can be written as .
Multiply and divide by .
Let .
The zero of the Numerator is
\
The zero of the denominator is
\
Therefore has
real zeros at
and
.
Create a sign chart using the value and
.
Note : The solid circle denote that the value are included in the solution set.
\The hallow circle denote that the value are not included in the solution set.
\Observe the sign chart :
\The set of value of denoted in blue color represents the solution set.
Determine whether is positive or negative on the test intervals.
Test intervals are and
.
If then
.
If then
.
If then
.
The solutions of are
values such that
is positive or equal to
.
From the sign chart, you can see that the solution set is .
The solution set is .
The solution set of is
.