The expression is .
The expression is to be defined only when .
Let .
The above expression is in the form of .
.
.
Therefore the factored form of is
.
The real zeros of are
Therefore has
real zeros at
and
.
Create a sign chart using the values and
.
Note : The solid circle denote that the value are included in the solution set.
\Determine whether is positive or negative on the test intervals.
Test intervals are and
.
If then
.
If then
If then
.
The solutions of are
values for which
is positive or equal to
.
The solution set is .
Therefore the domain is .
The domain is .