The inequality is .
The inequality can be written as .
Identify Possible Rational Zero:
\Usually it is not practical to test all possible zeros of a polynomial function
\using only synthetic substitution.
\The Rational Zero Theorem can be used for finding the some possible zeros to test.
\The function is .
Because the leading coefficient is , the possible rational zeros are the
integer factors of the constant term .
or
Therefore, the possible rational zeros of are
.
Perform the synthetic division method by testing .
Since , conclude that
is a zero of
.
Therefore is a rational zero.
The remaining quadratic factor is can be written as
.
The factored form of is
.
Therefore the zeros are and
.
Create a sign chart using the values and
.
Note: The hallow circle denote that the value are included in the solution set.
\Observe the sign chart:
\The set of value of denoted in blue color represents the solution set.
Determine whether is positive or negative on the test intervals.
Test intervals are and
.
Subustiute the values in the equation .
If then
.
If then
.
If then
.
If then
.
If then
.
The solutions of are
values for which
is negative.
The solution set is .
The solution set of is
.