The inequality is .
is non negative.
Consider .
Since .
.
Let .
is positive for all values of
.
Consider .
The zeros of are at
and
.
The zeros of are at
and
.
Draw a sign chart by using the values and
.
Note : The hallow circle denote that the value are excluded in the solution set.
\Observe the sign chart :
\The set of value of denoted in blue color represents the solution set.
The zero at is the location of sign change because it has multiplicity
.
\
The zero at is not the location of sign change because it has multiplicity
.
Test intervals are and
.
Subustiute the values in the inequality .
If then
.
If then
.
If then
.
The solutions of are
values such that
is positive.
From the sign chart the solution is .
From the sign chart,the solution set is .
The solution set of is
.
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\
\