The inequality is .
is non negative.
Consider .
is in the form of
.
.
Therefore .
Let .
The zeros of are at
and
.
The zeros of are at
and
.
Draw a sign chart by using the values and
.
Note: The solid circle denote that the value are included in the solution set. \ \
\Observe the sign chart:
\The set of value of denoted in blue color represents the solution set.
Because the zeros at and
has multiplicity
there is no location of sign change.
The solutions of are
values such that
is positive or equal to
.
From the sign chart the solution is set of all real numbers.
\From the sign chart, the solution set is .
The solution set of is
.