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The function is \"\".

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Rewrite the function as \"\".

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Graph the function \"\".

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\"\"

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Observe the graph :

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Domain set is \"\".

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Confirm the domain of the function algebraically :

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All possible values of \"\" is the domain of a function.

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The rational function \"\".

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The denominator of the function should not be the zero.

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\"\"

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\"\" and \"\".

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\"\", \"\" and \"\".

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Therefore, the domain of the function is all real values of \"\" except \"\", \"\" and \"\" .

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The domain set is \"\".

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\"\"

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\"\"

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\"\"

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Hole of the function is \"\".

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According to algebraic confirmation, \"\" must also excluded from the domain.

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The domain set is \"\".

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The domain set is \"\".