The two lengths of triangle are and
.
The angle is .
is acute .
Therefore, there are two solutions.
\There are two posibilities to draw the triangle with above specifications.
\Posibilty 1:
\
Consider triangle
\Law of sines : .
The sum of the angles in any triangle is .
The two angles are and
.
The remaining angle .
.
Law of sines : .
.
Therefore, the area of triangle is
Substitute and
and
in the above equation
Posibility 2:
\
Consider above triangle
\Law of sines : .
The sum of the angles in any triangle is .
The two angles are and
.
The remaining angle .
.
Law of sines : .
.
Therefore, the area of triangle is
Substitute and
and
in the above equation
.
Therefore, the third side of triangle is or
.
The third side of triangle is or
.