\"\"

\

\"\" feet per second at a bearing of \"\".

\

\"\" feet per second at a bearing of \"\".

\

Draw a diagram to represent \"\" and \"\" using a scale of \"\".

\

\"\"

\

Observe the diagram :

\

The angle created by \"\" and \"\" - axis is \"\".

\

Draw a horizontal where the tip of \"\" and the tail of \"\" meet, as shown in above figure.

\

\"\" makes a \"\" angle and \"\" makes a \"\" angle with the horizontal.

\

Thus, the angle created by \"\" and \"\" is \"\".

\

\"\"

\

Draw the resultant \"\".

\

The three vectors form a triangle.

\

\"\"

\

Use the law of cosines to find the magnitude of \"\".

\

Law of cosines : \"\".

\

\"\"

\

\"\"

\

Use the law of sines to find the angle opposite of \"\".

\

\"\"

\

Therefore, the angle opposite of \"\" is about \"\".

\

\"\"

\

To find the bearing of \"\", subtract \"\" from \"\".

\

Thus, the direction of \"\" is a bearing of \"\".

\

Since the equilibrant vector is the opposite of resultant vector, it will have a magnitude of about \"\" at a bearing of about \"\".

\

\

The magnitude of the quilibrant vector is about \"\"  at a bearing of about \"\".