\"\"

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a.

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Tensions of two cables are \"\" and \"\".

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Let the horizontal component of \"\" is \"\".

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The vertical component of \"\" is \"\".

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the horizontal component of \"\" is \"\".

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The vertical component of \"\" is \"\".

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Redraw the diagram as shown in below :

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\"\"

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Observe the diagram :

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\"\" and \"\" are right triangles.

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Find the horizontal component of \"\", i.e, \"\" by using the cosine ratio.

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In \"\", \"\".

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\"\"

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\"\".

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The horizontal component of \"\" is \"\".

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\"\"

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Find the vertical component of \"\",i.e, \"\" by using the sine ratio.

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In \"\", \"\".

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\"\"

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\"\".

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The vertical component of \"\" is \"\".

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\"\"

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Find the horizontal component of \"\", i.e, \"\" by using the cosine ratio.

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In \"\", \"\".

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\"\"

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\"\".

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The horizontal component of \"\" is \"\".

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\"\"

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Find the vertical component of \"\", i.e, \"\" by using the sine ratio.

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In \"\", \"\".

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\"\"

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\"\".

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The vertical component of \"\" is \"\".

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\"\"

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b.

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Find the magnitude of the vector, \"\", by using the cosine ratio.

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\"\"

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Thus, the magnitude of the vector is about \"\".

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\"\"

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c.

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Find magnitudes of horizontal and vertical components of \"\" and \"\".

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The horizontal component of \"\" is \"\".

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Magnitude of horizontal component of \"\" :

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The vertical component of \"\" is \"\".

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The horizontal component of \"\" is \"\".

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The vertical component of \"\" is \"\".

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a.

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\"\"; \"\"; \"\"; \"\".

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b.

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\"\"; \"\".

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c.