\"\"

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(a)

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Kyle is pushing the handle of the wheelbarrow down with a force of \"\" at an angle of 48° with the ground. Draw a vector to represent the handle of the wheelbarrow.

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\"\"

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Observe the figure,

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The vector can be resolved into horizontal component \"\" and vertical components \"\".

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Remove the axes.

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\"\"

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\"\"

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The horizontal and vertical components of the vector form a right triangle. Use the sine or cosine ratios to find the magnitude of each component.

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\"\"

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Observe the figure:

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\"\"

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Therefore magnitude of horizontal component is \"\".

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\"\"

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Therefore magnitude of vertical component is \"\".

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\"\"

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(a)

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\"\"

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(b)

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Magnitude of horizontal component is \"\" and magnitude of vertical component is \"\".