(a)
\The polar equation is .
where is measured in tens of thousands of miles.
Construct a table and calculate the values of on
.
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
![]() | \
Graph:
\1. Draw a polar coordinate plane.
\2. Use the points and polar axis symmetry to sketch the curve.
\(b)
\Observe the graph:
\The minimum distance the satellite will be from the earth occurs at .
Substitute in
.
Hence at ,
tens of thousand miles.
Therefore the minimum distance is miles.
The maximum distance the satellite will be from earth occurs at .
Substitute in
.
Hence at ,
tens of thousand miles.
Therefore the maximum distance is miles.
(c)
\The second satellite rectangular coordinates are .
Find polar coordinates .
Find :
.
Substitute in the above equation.
Find :
Since , the angle is
.
Substitute in the above equation.
The second satellite passes through the point with polar coordinates .
Find the location of first satellite, Substitute in
.
Hence for first satellite and
for second satellite.
So the two satellites are tens of thousand miles apart.
Therefore, the two satellites are miles apart, hence do not collide.
(a)
\Graph the polar equtaion .
(b) The maximum distance is miles and the minimum distance is
miles.
(c) The two satellites are miles apart and they do not collide.