The cubic function is .
Consider .
The function is having horizontal tangents at points and
.
The point passes through the curve.
Substitute in
.
The point passes through the curve.
Substitute in
.
If the curve has horizontal tangent at
, then slope of the tangent line is zero.
.
The curve has horizontal tangent at
.
Therefore, .
Substitute in above expression then equate
.
The curve has horizontal tangent at
.
Therefore, .
Substitute in above expression then equate
.
Solve and
to get
and
values.
Subtract the equation from
.
Add equations (1) and (2).
\Substitute in above expression.
Substitute in equation
.
Substitute ,
and
in equation
.
Substitute in
.
Substitute and
in cubic function
.
\
.