\"\"

(a)

Observe the graph.

At \"x=-4\" the function is \"2\" units below \"x-\" axis.

Therefore the point \"(-4, lies on the graph \"f(x)\".

Hence, \"f(-4)=-2\".

At \"x=3\" the function is \"4\" units above \"x-\" axis.

Therefore the point \"(3, lies on the graph \"g(x)\".

Hence, \"g(3)=4\".

\"\"

(b)

Find the value of \"x\" where the graph \"f(x)=g(x)\".

Observe the graph.

The values of \"x\" for which the \"y\" values of both the functions are equal.

At \"x=-2\", the functions \"f\" and \"g\" are \"1\" unit above \"x-\" axis.

Therefore the point \"(-2, lies on the graph.

Hence, \"f(-2)=1\" and \"g(-2)=1\".

At \"x=2\", the functions \"f\" and \"g\" are \"2\" units above \"x-\" axis.

Therefore the point \"(2, lies on the graph.

Hence, \"f(2)=2\" and \"g(2)=2\".

The values of \"x\" are \"-2\" and \"2\".

\"\"

(c)

Find the value of \"x\" where the graph \"f(x)=-1\".

Observe the graph.

\"f(x)=-1\" at \"x=-3\" and \"x=4\".

Hence, \"f(-3)=-1\" and \"f(4)=-1\".

\"\"

(d)

Observe the graph.

\"f(x)\" decreases for all values of \"x\" between \"0\\leqslant.

\"f(x)\" decreases on the interval \"\\left.

\"\"

(e)

The domain of \"f\" consists of all values of \"x\" on the graph of \"f\".

\"f(x)\" is defined for \"-4\\leqslant.

The domain of \"f\" is \"\\left.

The range of \"f\" consists of all values of \"y\" on the graph of \"f\".

\"f\" takes all the value from \"-2\" to \"3\".

The range of \"f\" is \"\\left.

\"\"

(f)

The domain of \"g\" consists of all values of \"x\" on the graph of \"g\".

\"g(x)\" is defined for \"-4\\leqslant.

The domain of \"g\" is \"\\left.

The range of \"g\" consists of all values of \"y\" on the graph of \"g\".

\"g\" takes all the value from \"0.5\" to \"4\".

The range of \"g\" is \"\\left.

\"\"

(a) \"f(-4)=-2\" and \"g(3)=4\".

(b) The values of \"x\" are \"-2\" and \"2\".

(c) \"x=-3\" and \"x=4\".

(d) \"\\left.

(e) Domain of \"f\" is \"\\left and range of \"f\" is \"\\left.

(f) Domain of \"g\" is \"\\left and range of \"g\" is \"\\left.