\
The function .
Find the horizontal asymptote.
\Therefore the horizontal asymptote is at .
Find the vertical asymptote.
\To find the vertical asymptote, equate denominator of the function to zero.
\So .
Therefore the vertical asymptote is at .
\
The function is .
Apply derivative on each side with respect to .
Find the critical points.
\Here is never zero, but it is undefined at
.
The critical point is .
The test intervals are and
.
Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Decreasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
The function is decreasing on the interval .
So there is neither local maximum nor local minimum, since the function is decreasing on .
\
Concavity :
\.
Again apply derivative on each side with respect to .
is never zero, but it is undefined at
.
There is no inflection points.
\Consider the test interval are and
.
\
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
| \
Down | \
![]() | \
![]() | \
\
| \
\
Up \ | \
The graph is concave up on the interval .
The graph is concave down on the interval .
\
Graph :
\Graph the function :
\
The horizontal asymptote is .
The function is decreasing on .
The graph is concave up on and concave down on
.
Graph of the function is
.