\
The function is .
(A)
\Domain :
\The function is .
All possible values of is the domain of the function.
Denominator of the function should not be zero
\ and
.
The domain of the function is
.
\
(B)
\Intercepts :
\To find the -intercepts, substitute
in the function.
Therefore the -intercept is
.
To find the -intercepts, substitute
in the function.
Since at , the functionis not defined
.
Therefore the -intercepts is
.
\
(C)
\Symmetry :
\Substitute in the function.
Here
Therefore the function is neither odd nor even.
\
(D)
\Asymptotes :
\Horizontal asymptote :
\Therefore the horizontal asymptote is .
Vertical asymptote :
\Vertical asymptote appears when the function is not defined.
\Since at , the functionis not defined.
Therefore the vertical asymptote is .
\
(E)
\Intervals of increase or decrease :
\The function is .
Differentiate on each side with respect to
.
is never zero and the function is positive for the domain of
.
Therefore is increasing over its domain.
\
(F)
\Local Maximum and Minimum values :
\From (E) it is clear that the function is only increasing.
\Therefore is no local minimum or maximum values.
\\
(G)
\Concavity and point of inflection :
\.
Differentiate on each side with respect to
.
Find inflection point.
\ is never zero.
There is no inflection point.
\But at and
, the function is undefined, so split the intervals into
,
and
.
\
Interval \ | \
Test Value | \Sign of ![]() | \
Concavity | \
![]() | \
![]() | \
\
\ | \
Up | \
![]() | \
![]() | \
\
| \
\
\ Up \ | \
![]() | \
![]() | \
\
\ | \
Down | \
The graph is concave up in the interval ,
.
The graph is concave down in the interval .
\
(H)
\Graph :
\Graph of the function :
\
(A) The domain of the function is
.
(B) -intercept is
and
-intercepts are
.
(C) No symmetry.
\(D) The horizontal asymptote is and the vertical asymptote is
.
(E) Increasing on ,
and
.
(F) There is neither local minimum nor local maximum.
\(G) Concave up on and
.
concave down on .
(H) Graph of the function is
.