The integral is .
Rewrite the integral as .
Consider .
Here the integrand function is an odd function.
\From the symmetric property of the integrals, .
Consider .
Determine the integral interms of an area.
\Find the area of the region under the curve using graphing utility.
\Graphically the area of the region under the curve is .
.
Required integral is three times the area of the semicircle.
\Therefore, .
Substitute results of and
in
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