The function is and the interval is
.
(a)
\Average value of the function on
is defined as
.
Here .
Average value of is
.
Average value of the function on
is
.
(b)
\Find such that
.
Consider .
We have .
Substitute and
in
.
.
Since it is very difficult to find the roots by solving the trigonometric equation, use the graph to find value.
Graph:
\Graph the functions and
.
From the graph,
\It is observed that, intersection points are and
.
The values of are
-coordinates of the points.
and
.
(c)
\Graph the function and rectangle under the interval
.
(a)
\Average value of the function on
is
.
(b) The values of are
and
.
(c) Graph:
\.