The function is ,
.
Apply derivative on each side with respect to .
Find the critical numbers of , by equating
to zero.
.
Since then test intervals are
and
.
Interval | \![]() | \
Sign | \
![]() | \
\
| \
Decreasing | \
![]() | \
\
| \
Increasing | \
Therefore is decreasing on
and increasing on
.
As changes its sign from positive to negative,
has an absolute minimum at
.
Substitute in
.
Absolute minimum of the function is .
Absolute minimum of the function is .