A cardiac monitor is used to measure the heart rate of a patient after surgery.
\The number of patients heartbeats are taken in the table for different values of time .
Find the slope of the secant lines between the points using the table of values.
\(a)
\Find the slope at and
.
At and the corresponding patient heartbeat is
.
At and the corresponding the patient heartbeat is
.
So the obtained points are and
.
Slope of the two points is .
The slope of the secant line is heartbeats/min.
(b)
\Find the slope at and
.
At and the corresponding patient heartbeat is
.
At and the corresponding the patient heartbeat is
.
So the obtained points are and
.
Slope of the two points is .
The slope of the secant line is heartbeats/min.
(c)
\Find the slope at and
.
At and the corresponding patient heartbeat is
.
At and the corresponding the patient heartbeat is
.
So the obtained points are and
.
Slope of the two points is .
The slope of the secant line is heartbeats/min.
(d)
\Find the slope at and
.
At and the corresponding patient heartbeat is
.
At and the corresponding the patient heartbeat is
.
So the obtained points are and
.
Slope of the two points is .
The slope of the secant line is heartbeats/min.
Conclusion :
\After minutes the patients heart rate decreases.
Find the patient heart rate after minutes.
Use the average of the slopes of the patients heart rate after minutes.
So consider the points near to are
and
.
The slope of the heart rate at and
is
heartbeats/min.
The slope of the heart rate at and
is
heartbeats/min.
The average of the slopes is heartbeats/min.
The patient heart rate after minutes is
heartbeats/min.
(a) heartbeats/min.
(b) heartbeats/min.
(c) heartbeats/min.
(d) heartbeats/min.
The patient heart rate after minutes is
heartbeats/min.