$\"\"$

\

If $\"\"$ and $\"\"$ .

\

The integral expression is $\"\"$ .

\

Consider the fact that $\"\"$ is greater than $\"\"$ , since denominator is small in the first expression.

\

Consider $\"\"$ .

\

$\"\"$

\

Since $\"\"$ then $\"\"$ and it is some negative number.

\

Let $\"\"$ .

\

$\"\"$

\

$\"\"$ which results a finite number, therefore $\"\"$ is convergent.

\

From the comparison theorem:

\

Suppose $\"\"$ and $\"\"$ are continuous functions with $\"\"$ and

\

If $\"\"$ is convergent then $\"\"$ is also convergent.

\

Therefore, if $\"\"$ then $\"\"$ is also convergent.

\

$\"\"$

\

$\"\"$ is convergent.