![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
Locate a midpoint between – 5 and 5 on number line daigram.![\"absolute](\"/userfiles/image/Library/Algebra1/absolute_value_midpoint_0_and_end_points_-5_to_5.gif\")
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step2.JPG\")
Find the distance between midpoint 0 and end points – 5 and 5.
\The distance from – 5 to 0 is 5 units.
\The distance from 0 to 5 is 5 units.
\Since the distance is 5 units the absolute value equation is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=1fe19dbbf70cbdb5bea503c292c49589.png\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=102f377aee24c10b7d225782e584890c.png\")
(Addititve identity property: ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=19b808e0e1ea635c61c5cb951a78f2d7.png\")
)![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
Absolute value equation is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=102f377aee24c10b7d225782e584890c.png\")
.