![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
Locate a midpoint between – 2 and 8 on number line daigram.![\"absolute](\"/userfiles/image/Library/Algebra1/absolute_value_midpoint_3_and_end_points_-2_to_8.gif\")
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step2.JPG\")
Find the distance between midpoint 3 and end points – 2 and 8.
\The distance from – 2 to 3 is 5 units.
\The distance from 3 to 8 is 5 units.
\Since the distance is 5 units the absolute value equation is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=fa4b59e1c2a3e10fb35e2ac67ee262ad.png\")
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
Absolute value equation is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=fa4b59e1c2a3e10fb35e2ac67ee262ad.png\")
.