![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
Locate a midpoint between – 3 and 5 on number line daigram.![\"absolute](\"/userfiles/image/Library/Algebra1/absolute_value_midpoint_1_and_end_points_-3_to_5.gif\")
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step2.JPG\")
Find the distance between midpoint 1 and end points – 3 and 5.
\The distance from – 3 to 1 is 4 units.
\The distance from 1 to 5 is 4 units.
\Since the distance is 4 units the absolute value equation is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=a377b079241024a0b7f826741b670a07.png\")
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
Absolute value equation is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=a377b079241024a0b7f826741b670a07.png\")
.