![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
Locate a midpoint between – 2 and 4 on number line daigram.![\"\"](\"/userfiles/image/Library/Algebra1/absolute_value_equation_3units_number_line_graph.gif\")
![\"\"](\"/userfiles/image/steps_images/step2.JPG\")
Find the distance between midpoint 1 and end points – 2 and 4.
\The distance from – 2 to 1 is 3 units. \ \
\The distance from 1 to 4 is 3 units.
\Since the distance is 3 units the absolute value equation is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=b21e6b77b46594f5e1dcdbb17e1b48dd.png\")
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
Absolute value equation is ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=b21e6b77b46594f5e1dcdbb17e1b48dd.png\")
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